OK, first things first, a little math to determine the area of air that we need to move..... I'm assuming an 8' ceiling, but will expose the math so you can sub a number if needed....
You have 64 square feet. That is 8' x 8' walls, 64 single foot squares. In order to determine volume, we have to multiply the square footage by the height, so 64 * 8' gives us 512 cubic feet. Now that we have the volume, we need to determine how many times per minute we need to replace that air. If you are using a sealed room and plan to introduce CO2, you'll want a fan that can cycle the room air 5 times per minute, so it can quickly clear the area when cycled on. A 24 hour exhaust fan to maintain negative pressure and control odor probably needs to cycle the air 3 times per minute.
How ever many times you want to exchange the air per minute is up to you. 3-5 is recommended. So let's look at the formula...
l x w x h = cf / pm = cfm
Length times width times height = cubic footage divided by cycles per minute equals desired cfm of exhaust fan.
We already have the volume, 512 cf so we divide by the number of cycles, for example 3, we get 170 cfm. Keep in mind that this doesn't reflect pulling air through lights or a carbon filter. This formula is simply for air exchange.
When you add the light (approx 350 cfm per 1kw), you can now account for heat exchange as well. So using the same example as above, if you had 2k watts of light (2 1k in an 8'x8') You are looking at a requirement of 870 cf/m, and we haven't factored in duct loss and back pressure yet.
You'll also need to take into consideration the resistance from the charcoal filter/scrubber. In our example, I would use a fan with a cfm rating of about 1100 cfm. Fans that size require 12" ducting, so it maybe ideal to split the requirement and run two exhaust fans, however you'll need two controllers and two scrubbers.
I hope this info was handy.