What Dimmers/Switches for 2 HLG-185H-C1050B and 10xcxb3070

Hey all I am upgrading my first very basic DIY LED fixture. I currently have 2cxa z2 and 2cxb ab on a 40 inch piece of of heatsinkUSA 8.46 profile (which is overkill on cooling), being run by individual meanwell 1.4ma drivers.

I just bought 10x CXB 3070 BB to put on that same heatsink and I will use the older less efficient COBs in individual or paired setups to be used for mothers, clones, etc.

I got 2 HLG 185H-C1050B to run my 10 cxb 3070. I would like to have each driver have its own switch and dimmer. What kind of dimmer and switch do I need? If there is a way to dim to only about 30% as a cutoff it looks like that is where the driver starts to get bad efficiency. I tried looking at the dimming section on the driver sheet but I am not great with electrical and so I am still a bit confused. Any help would be appreciated, suggestions welcome.

Thanks

You need a 100kohm Petentiometer https://www.google.co.uk/search?q=Petentiometer&oq=Petentiometer&aqs=chrome..69i57&sourceid=chrome&es_sm=122&ie=UTF-8

Id like to know if you can wire up 4 drivers with just one of these ?

This table is in the data sheet:


Reggae, if you wire a 30Kohm resister in series with a 100Kohm (or 70K, whatever) potentiometer, the current will never be less than 30%.
If you really want an integrated off switch, there is a relay diagram in the data sheet.

Looks like skorchem would want a 25Kohm pot.

sanjuan said:

This table is in the data sheet:
View attachment 3601107

Reggae, if you wire a 30Kohm resister in series with a 100Kohm (or 70K, whatever) potentiometer, the current will never be less than 30%.
If you really want an integrated off switch, there is a relay diagram in the data sheet.

Looks like skorchem would want a 25Kohm pot.

Click to expand...

Awesome thanks man, I got all fired up and ordered more COBs and Drivers to realize I wasn't sure how to wire it up haha.

sanjuan said:

This table is in the data sheet:
View attachment 3601107

Reggae, if you wire a 30Kohm resister in series with a 100Kohm (or 70K, whatever) potentiometer, the current will never be less than 30%.
If you really want an integrated off switch, there is a relay diagram in the data sheet.

Looks like skorchem would want a 25Kohm pot.

Click to expand...

Also if I wanted my 2 drivers on the same I understand I would need a 50k pot, would it still be a 30Kohm resistor?

No, the table shows (30Kohm / n) where n = number of drivers so 15Kohm in series with a 50Kohm pot will control two drivers.

ok got pots ordered on the resistors there is a range of wattage (all under 5 w) and varying tolerance. Wattage is just going to affect total draw and tolerance reflects how close to the exact ohm rating?

The watt rating of a resistor (pot) is the amount of power it can handle without burning up. This is just a control circuit for the driver; currents and voltage will be low; thus, low power.

You are correct about tolerance and it doesn't really matter in this application.

skorchem said:

You need a 100kohm Petentiometer https://www.google.co.uk/search?q=Petentiometer&oq=Petentiometer&aqs=chrome..69i57&sourceid=chrome&es_sm=122&ie=UTF-8

Id like to know if you can wire up 4 drivers with just one of these ?

Click to expand...

Yup. 1 driver is 100k pot
2 of the same amperage & wattage would be 50k
3= 33-35k
4=(what you asked about) 25k pot.
This is applied when all drivers are put on one power cord. All drivers wired together.

sanjuan said:

The watt rating of a resistor (pot) is the amount of power it can handle without burning up. This is just a control circuit for the driver; currents and voltage will be low; thus, low power.

You are correct about tolerance and it doesn't really matter in this application.

Click to expand...

sanjuan said:

The watt rating of a resistor (pot) is the amount of power it can handle without burning up. This is just a control circuit for the driver; currents and voltage will be low; thus, low power.

You are correct about tolerance and it doesn't really matter in this application.

Click to expand...

What should wattage of my resistors be on the control loop? You say very low but it also does not seem to say on the spec sheet unless I am not understanding some of the spec. Thanks for all the help btw.

Any resistor will work. I used 1/2 watt just because they're easy to work with and heatshrink up next to nice and snug. They're not much bigger than the shrink wrap. Just make sure the resistor number is equal to 10% of the potentiometer. 100k-10k. 50k-5k. 33k-3.3k. 25k-2.5k. If radio shacks drawer stock is low which it usually is, just buy however many you need of the same wattage to equal the number.
I.e 2 5ks for 10 or 2 2.5ks for 5 and just solder them one after another.