Canadian Farmer
Well-Known Member
Hey guys, I have a question. How many Vero29 COBs would you need to equate the light output of a double ended HPS 1000 in a SunMaster AC/DE reflector ?
Cool story bro, but your DE is operating at 1150W, 250W more than the vero, NOT 1000W to get those numbers...at 1000W its pulling 1950umol according to the hortilux site, so vero wins, and how many times will you need to change those $120 bulbs before you need to change out 1 vero chip to keep those numbers? tell me that?????That's an outright lie , 1000w DE lights produce ~2100umol , 700w of vero29's won't even come close to that.
http://timbergrowlights.com/fatty-vs-5x5/
POWER:
Total Wattage: 900 Watts
PAR Wattage: 450 PAR Watts
PPF: 2097 μmol/s
900w of vero 29's still produces less light than a 1000w DE light does on overdrive.
900w vero 29 = 2039 umol
1150w de = 2100umol
https://growershouse.com/hortilux-de-double-ended-hps-1000w-lamp
FEATURES
- Available wattages: 1000w
- Exclusive EYE HORTILUX Spectrum promotes bigger, fuller flower growth with higher quality yields.
- Provides 1950 µmol when operated at 1000w.
- Provides 2100 µmol when operated at 1150w.
You LED guys might wanna get some facts before making outrageous claims to sell your shitty LEDs. The DE light also has the superior spectrum.
Because some LED guys hate it when the HPS lamp users talk about HPS being a good light source for cannabis.why do these threads always turn into a shit show?
What’s the sq ft coverage on a setup like this?Vero 29C 3000K 90 CRI, LER-280 and QER-5
At .7 amps and 40C Tc output is 45.3 watts, 158 LPW = 56.43% efficiency
45.3 x .5643 = 25.56 PAR watts
25.56 x 5 = 127.8 PPF (127.8 / 45.3 = 2.82 umol/j) (want to run them at .5 amps? 3 umol/j)
1950 / 127.8 = 15.26
So at .7 amps it more or less takes 15 cobs to equal a 1000w DE
15 x 45.3 = 679.5 watts. Throw in the extra .26 and it's still under 700w.
It might be a stretch to suggest it can be done with 10 cobs.
At 1.05 amps, 69.8 watts, 144 LPW = 51.43% efficiency
69.8 x .5143 = 35.9 PAR watts
35.9 x 5 = 179 PPF (179 / 69.8 = 2.56 umol/j)
1950 / 179 = 10.89
At 1.05 amps it takes 11 cobs to equal a 1000w DE
11 x 69.8 = 768 watts.
If we want to be picky and remove that tenth of a cob it comes out to 760 watts.
However, maybe 10 (698 watts) would provide a similar PPFD. Anyone have both and a par meter?
Which spectrum is superior? Opinions are cheap. Anyone done the testing? 1:1 Par watt vs Par watt in a controlled environment? Or better, equal PPFD across the canopy vs equal PPFD across the canopy? I suspect not. 3000K 90CRI has a very nice spectrum... anecdotal evidence doesn't seem to indicate a huge advantage between various white spectrums anyway.
Depends on what kind of intensity you want. Using some loose math (it will vary based on spectrum used, but not a lot),What’s the sq ft coverage on a setup like this?
Quoting myself, @Greengenes707 I think has done both under a meter. Not specifically Vero 29, but I bet he can provide some insight.Anyone have both and a par meter?
Its all about putting the puzzle together. Yea you want to take Rivers and Keenan, but Norman is getting someone. So Benjamin may be the play? 3,800.00 for christ sakes!!!!!Quoting myself, @Greengenes707 I think has done both under a meter. Not specifically Vero 29, but I bet he can provide some insight.
So it is safe to say that best numbers are achieved in a 4x4 area? Wouldn’t it be more camparable to a 600/750 de in coverage since 1000w de is meant to be mounted much higher and therefore covering a much larger footprint that a 4x4. I mean going from a 4x4 to a 5x5 you are saying the PPFD is cut almost in half.Depends on what kind of intensity you want. Using some loose math (it will vary based on spectrum used, but not a lot),
15 PAR watts per foot (750 PPFD)
20 PAR watts per foot (1000 PPFD)
25 PAR watts per foot (1250 PPFD)
You can figure out the coverage depending on what intensity you'd like to work with. For instance, using the .7 amp option and 15 cobs, 383 par watts. To get 1000 PPFD, 383 / 20 = 19.15 square feet. in a 5x5 it will be closer to 800 PPFD. In a 4x4 it will be a tad over 1200 PPFD. It will be similar for the other examples I gave since they all have similar radiant output.
The "best" numbers depend on whether you're trying to maximize phototrophic efficiency, in which case you would be better off in a 5x5. It's only in the last year or two that people in the LED community have been intentionally trying to push the PPFD to 1000 and beyond. I've never used even 800 PPFD and yet managed to yield 60 grams per square foot. I'm sure peeps have done better with similar light levels as I don't consider myself a great grower, but 800 isn't weak sauce. Almost nobody outside the LED community is growing with +1000 PPFD. If you want to hit close to 1200 PPFD with DEs, try putting 3 600w bulbs over a 4x8. 1000w over 5x5 isn't going to do it. Even if you are running 1150 watts you still won't have a 1000 PPFD average.So it is safe to say that best numbers are achieved in a 4x4 area?
not my experience... i personally seem to run into limitations at higher ppfdIt is true that whatever 800 PPFD can do, 1000 PPFD can do better
I find this to be true as well at least in my soil grow. The difference between running bro science soil mix loaded with everything the rols or organic crowd suggest vs running a tuned, tested, base saturation in balance soil is critical to success in high ppfdIt is true that whatever 800 PPFD can do, 1000 PPFD can do better (g/sqft), and while there is evidence that the yield curve is more linear than the vegetative curve, logically it's still going to be a matter of diminishing returns. .