is this the right way to calculate your nutrient mix?
- Thread starter glann
- Start date
cannabineer
Ursus marijanus
It's not quite that simple.
5-0-1 is NPK in per cent, but P is calc'd as P2O5 and K as K2O, ... so actual P and K are 43.6% and 83% of the quoted values.
1% K2O is actually 0.83% K. 1 ml in 1 gallon (call it 3800 ml) will yield 2.18 ppm K.
cn
5-0-1 is NPK in per cent, but P is calc'd as P2O5 and K as K2O, ... so actual P and K are 43.6% and 83% of the quoted values.
1% K2O is actually 0.83% K. 1 ml in 1 gallon (call it 3800 ml) will yield 2.18 ppm K.
cn
Me to i still dnt understand
cannabineer
Ursus marijanus
You need the conversion factors to convert the numbers on dilution:
% P2O5 to ppm P
% K2O to ppm K
N is given as N, so no conversion factor is needed.
An example: Bloom is 5% stated P, and say you want 50 ppm final P in your nutrient solution.
So do you mix it 1 to 1000? (5% is 1000x 50 ppm) No. the stated 5% are calculated as P2O5. You'd end up with 43.6% x 50 ppm = 21.8 ppm. To arrive at the desired 50 ppm youneed to use 2.29 times as much. (1 divided by .436 is about 2.29)
cn
% P2O5 to ppm P
% K2O to ppm K
N is given as N, so no conversion factor is needed.
An example: Bloom is 5% stated P, and say you want 50 ppm final P in your nutrient solution.
So do you mix it 1 to 1000? (5% is 1000x 50 ppm) No. the stated 5% are calculated as P2O5. You'd end up with 43.6% x 50 ppm = 21.8 ppm. To arrive at the desired 50 ppm youneed to use 2.29 times as much. (1 divided by .436 is about 2.29)
cn
Me to i still dnt understand
squarepush3r
Well-Known Member
I believe he wants to do Lucas Formula. Yes, Lucas formula is 1 part micro, 2 parts bloom, which gives 5-10-9
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